Assignment Operators
 
 
  The basic assignment operator is "=". Your first inclination might
  be to think of this as "equal to". Don't. It really means that the
  left operand gets set to the value of the expression on the
  right (that is, "gets set to").
 
 
  The value of an assignment expression is the value assigned. That
  is, the value of "$a = 3" is 3. This allows you to do some tricky
  things:
  
   Example #1 Nested Assignments
   
<?php
$a = ($b = 4) + 5; // $a is equal to 9 now, and $b has been set to 4.
var_dump($a);
?>
    
   
 
 
  In addition to the basic assignment operator, there are "combined
  operators" for all of the binary
  arithmetic, array union and string operators that allow you to use a value in an
  expression and then set its value to the result of that expression. For
  example:
  
   Example #2 Combined Assignments
   
<?php
$a = 3;
$a += 5; // sets $a to 8, as if we had said: $a = $a + 5;
$b = "Hello ";
$b .= "There!"; // sets $b to "Hello There!", just like $b = $b . "There!";
var_dump($a, $b);
?>
    
   
 
 
  Note that the assignment copies the original variable to the new
  one (assignment by value), so changes to one will not affect the
  other. This may also have relevance if you need to copy something
  like a large array inside a tight loop.
 
 
  An exception to the usual assignment by value behaviour within PHP occurs
  with objects, which are assigned by reference.
  Objects may be explicitly copied via the clone keyword.
 
 
  Assignment by Reference
  
   Assignment by reference is also supported, using the
   "$var = &$othervar;" syntax.
   Assignment by reference means that both variables end up pointing at the
   same data, and nothing is copied anywhere.
  
  
   
    Example #3 Assigning by reference
    
<?php
$a = 3;
$b = &$a; // $b is a reference to $a
print "$a\n"; // prints 3
print "$b\n"; // prints 3
$a = 4; // change $a
print "$a\n"; // prints 4
print "$b\n"; // prints 4 as well, since $b is a reference to $a, which has
              // been changed
?>
     
    
  
  
   The new
   operator returns a reference automatically, as such assigning the result of
   new by reference is an error.
  
  
   
    Example #4 new Operator By-Reference
    
<?php
class C {}
$o = &new C;
?>
     
    The above example will output:
Parse error: syntax error, unexpected token ";", expecting "("
 
    
  
  
   More information on references and their potential uses can be found in
   the References Explained
   section of the manual.
  
  
 
  Arithmetic Assignment Operators
  
  
 
  Bitwise Assignment Operators
  
  
 
  Other Assignment Operators